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Kevin jump straight up in the air to a height of 1 m at the top of his jump he has the potential energy of 1000 J answer the following question based on these numbers

A.what is Kevin’s weight

B.if Kevins potential energy at the highest point of the jump as 1,000 Joules,what is his speed when he leaves the ground?

Respuesta :

oladipupog80

Answer:

1000N,4.48m/s

Explanation:

Height(h) = 1m

P. E = 1000J

P. E = mass x acceleration due to gravity x height

Acceleration due to gravity = 10m/s

P. E = mgh

Where weight = mg

P. E = weight x height

Weight = P. E / height

Weight = 1000 / 1

Weight. 1000N

b) as he leaves the ground P. E = K. E

P. E = 1/2 mv2

P. E = 1000 , mass = weight / 10

                      Mass =1000/10 = 100kg

P. E = 1/2 mv2

1000 = 1/2 x 100 x v2

Multiply both sides by 2

1000 x 2 = 100 x v2

V2 = 2000/ 100

V2 =20

Square root both sides

V = square root of 20

V = 4.48m/s

I hope this was helpful, Please mark as brainliest

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