The maximum mass of NaCl is 0.54 g.
Explanation:
The reaction can be represented with the following equation:
HCl + NaOH ----> NaCl + H2O
According to the equation, equal amounts of chemical agents and resultant products (in moles) participate in this reaction.
The amount of hydrochloric acid is as follows:
[tex]v_{HCl} = \frac{m_{HCl} }{M_{HCl} }[/tex] [tex]= \frac{m_{HCl} }{A_{H} + A_{Cl} }[/tex]
= 1.1 / (1 + 35.46)
[tex]v_{HCl}[/tex] = 0.030 moles.
where m is the mass,
A is the atomic mass of an element.
The amount of sodium hydroxide is as follows:
[tex]v_{NaOH} = \frac{m_{NaOH} }{M_{NaOH} } = \frac{m_{NaOH} }{A_{Na} + A_{O} + A_{H} }[/tex]
= 0.420 / (23 + 16 + 1)
= 0.0105 moles.
Since the amount of sodium hydroxide exceeds the amount of hydrochloric acid, the maximum amount of each substance participating in the reaction is v = [tex]v_{HCl}[/tex] = 0.030 moles.
Therefore, the maximum amount of water that can be produced is as follows:
[tex]m_{H2O} = M_{H2O} \times v_{H2O} = (2A_{H} + A_{O} ) \times v[/tex]
= (2 [tex]\times[/tex] 1 + 16) [tex]\times[/tex] 0.030 = 0.54 g.
The maximum mass of NaCl is 0.54 g.
