Answer:
a) 2.53 × 10²³ molecules of O₂
b) 31.90 g of KCl
Explanation:
The balance chemical equation for given decomposition reaction is as follow;
2 KClO₃ → 2 KCl + 3 O₂
Step 1: Calculate Moles for given amount of KClO₃;
Moles = Mass / M.Mass
Moles = 34.35 g / 122.55 g/mol
Moles = 0.280 moles of KClO₃
Step 2: Find out moles of O₂ produced;
According to eq,
2 moles of KClO₃ produces = 3 moles of O₂
So,
0.280 moles of KClO₃ will produce = X moles of O₂
Solving for X,
X = 0.280 mol × 3 mol / 2 mol
X = 0.42 moles of O₂
Step 3: Calculate No. of Molecules of O₂ as,
No. of Molecules = Moles × 6.022 × 10²³
No. of Molecules = 0.42 mol × 6.022 × 10²³ molecules/mol
No. of Molecules = 2.53 × 10²³ molecules of O₂
Step 1: Calculate Moles for given amount of KClO₃;
Moles = Mass / M.Mass
Moles = 52.53 g / 122.55 g/mol
Moles = 0.428 moles of KClO₃
Step 2: Find out moles of KCl produced;
According to eq,
2 moles of KClO₃ produces = 2 moles of KCl
So,
0.428 moles of KClO₃ will produce = X moles of KCl
Solving for X,
X = 0.428 mol × 2 mol / 2 mol
X = 0.428 moles of KCl
Step 3: Calculate Mass of KCl as;
Mass = Moles × M.Mass
Mass = 0.428 mol × 74.55 g/mol
Mass = 31.90 g of KCl
