Answer:
4028
Step-by-step explanation:
Fox number in 2010=1500
Rate of annual increase = 2.5 %
Fox number in 2050=?
This is compound interest problem
We use
A= P [tex](1+ \frac{R}{100}) ^{T}[/tex]
Where,
A= Fox number in 2050
P=fox number in 2010
R= 2.5
T= 40 years
Put values
==> A= 1500[tex](1+\frac{2.5}{100} )^{40}[/tex]
==> A= 1500 × [tex](1.025)^{40}[/tex]
==>A = 1500 × 2.6850638383=4027.6=4028
Answer:
Step-by-step explanation:
We would apply the formula for exponential growth which is expressed as
A = P(1 + r)^t
Where
A represents the population after t years.
t represents the number of years.
P represents the initial population.
r represents rate of growth.
From the information given,
P = 1500
r = 2.5% = 2.5/100 = 0.025
The number of years from 2010 to 2050 is 40 years. So
t = 40
Therefore, the expression that represents the fox population in the year 2050 is
A = 1500(1 + 0.025)^40
A = 1500(1.025)^40
