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An assistant for a football team carries a 26.0 kg cooler of water from the top row of the stadium, which is a distance h = 17.5 m above the field level, down to the bench area on the field. The speed of the cooler is constant throughout the trip. Calculate the work done by the assistant on the cooler of water.

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AL2006

The weight of the cooler is (mg). That's (26)(9.8) = 254.8 Newtons.

Its gravitational potential energy while it's up in the top row is (mgh). That's (254.8)(17.5) = 4,459 Joules.

That's how much work it took to get the cooler up to the top row, and that's the energy it gives up when it moves back down to the bench.

In order to bring it down . . .

-- Gravity does 4,459 joules of work on the cooler.

-- The team assistant does NEGATIVE 4,459 joules of work on it.

Cricetus

The work done by the assistant will be "4459 Joule".

The given values are:

Mass,

  • m = 26.0 kg

Distance,

  • h = 17.5 m

The work done by the gravity will be:

= [tex]Force\times distance\times Cos \theta[/tex]

By substituting the given values in the above formula, we get

= [tex]26\times 9.8\times 17.5\times 1[/tex]

= [tex]4459\times 1[/tex]

= [tex]4459 \ Joule[/tex]

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