a. so using the i method, you take one of the valuable on the horizontal side and multiply it by a valuable on the vertical side. So in this case, you would take x (horizontal side) and multiply it by x (vertical side) to get [tex]x^{2}[/tex]. Multiply x (horizontal side) by 1 (vertical side) to get x. Keep doing this so 1 multiplied by x to get x. 1 multiplied 1 to get 1. So the answer for now is [tex]x^{2}[/tex]+x+x+1. We can simplify it to get [tex]x^{2}[/tex]+2x+1. Using the ii method, the entire length of the horizontal side is x+1 (you just add the two valuables) and the entire length of the vertical side is also x+1 (again, add the two valuables). To find the area, just multiply (x+1)*(x+1) to get [tex]x^{2}[/tex]+2x+1.
b. using the i method, use the same method in a. you should get an answer of [tex]x^{2}[/tex]+2x-2. using the ii method, and the method i showed in a., you should get an answer of [tex]x^{2}[/tex]. These two answers visually aren't the same, but they actually are
