Respuesta :
Answer:
0.146 m
Explanation:
f = -KΔL according to Hooke's law
volume of water displaced = mass / density of block since a body will displace equal volume of its own
weight of water displaced = mass of water × acceleration due to gravity
and mass of water = volume of water / density of water
weight of water displaced = Vw × dw × g = mg (dw / dblock)
net force = mg - mg (dw / dblock) = 42.728 - 65.74 = -23.00
it will be balanced by a restoring force of 23 N
ΔL = F / k = 23 / 158 = 0.146 m
According to the Hooke's Law the force applied to compress or stretch the spring is directly proportional to the distance. The elongation of the spring is 0.146 m.
Hooke's Law:
It states that the force applied to compress or stretch the spring is directly proportional to the distance.
[tex]\bold{F = K \Delta L}[/tex]
Where,
K - spring constant = 158N/m
[tex]\bold{\Delta L}[/tex] - elongation
Given Here,
Weight of block - 4.36-kg
Density of block = 650 [tex]\bold {kg/m3}[/tex]
The net force on spring,
[tex]\bold{F = mg - mg (\frac{D_w}{D_b} )}[/tex]
[tex]\bold {F =42.728 - 65.74} \\\\\bold {F = 23 N}[/tex]
Put the value in the formula,
[tex]\bold { 23 = 158\times \Delta L}[/tex]
[tex]\bold { \Delta L = 0.146 m }[/tex]
Therefore, the elongation of the spring is 0.146 m.
To know more refer Hook's law, to the link:
https://brainly.com/question/10991960
