Answer:
-0.0133 < p < 0.10667
- It does include zero
Step-by-step explanation:
Given:
- The number of responses with certificate p_1 = 50
- The number of responses without certificate p_2 = 29
- Total sample size n = 350 adults
Find:
From 95% confidence interval for the difference of proportion. Does it include zero?
Solution:
- Formulate the proportion of people with and without certificate:
p_hat with certificate = p_1 / n = 50/350 = 1/7
p_hat w/o certificate = p_2 / n = 29/350 = 0.082857
- Next compute the critical value of 95% confidence interval:
Z_0.05 = 1.96
- The confidence interval is:
E = 1.96*sqrt [ (1/7)*(1-1/7)/350 + (0.082857)*( 1 -0.082857) / 350 ]
E = 0.04667
C.I : E - ( P_hat difference) < p < E + ( P_hat difference)
0.04667 - (0.06) < p < 0.04667 + (0.06)
-0.0133 < p < 0.10667
- It does include zero