The scatter plot shows the number of years of experience, , and the hourly pay rate, , for each of cashiers in California. x123456789101112y24681012141618200 Use the equation of the line of best fit, , to answer the questions below. Give exact answers, not rounded approximations. (a) For an increase of one year of experience, what is the predicted increase in the hourly pay rate? (b) What is the predicted hourly pay rate for a cashier who doesn't have any experience? (c) What is the predicted hourly pay rate for a cashier with years of experience?

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Answer:

a) $0.95

b) $7.95

c) $12.70

Step-by-step explanation:

Please refer to the diagram below to understand the complete question. The equation for line of best fit is: [tex]y = 0.95x + 7.95[/tex] ; where [tex]x[/tex] represents the number of years of experience and [tex]y[/tex] represents the hourly pay rate.

We use this equation to find the answers.

a) To find the pay rate increase per year of experience, we substitute [tex]x= 1[/tex] in the equation of line of best fit.

[tex]y = 0.95x + 7.95\\y=0.95 (1) + 7.95\\y=0.95 + 7.95\\y= 8.90[/tex]

and then [tex]x= 2[/tex]

[tex]y =0.95x +7.95\\y=0.95(2)+7.95\\y=1.90+7.95\\y=9.85\\\\[/tex]

Find the difference between both years:

9.85-8.90 = 0.95

Answer is $0.95

b) To find the pay of a cashier with zero experience, we substitute [tex]x=0[/tex] in the equation.

[tex]y = 0.95x +7.95\\y= 0.95(0)+7.95\\y=0+7.95\\y=7.95[/tex]

Answer is $7.95

c) A cashier with five years of experience, [tex]x=5[/tex] will receive:

[tex]y=0.95x + 7.95\\y=0.95(5) + 7.95\\y=4.75+7.95\\y=12.70\\[/tex]

Answer is $12.70

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Missing Part of Question:

As the question is missing information, I have searched for it and I am attaching one which closely resembles this one.

Answer:

Step-by-step explanation:

Given:

y = 0.9x + 8.3 -------------- (1)

Part (a):

Let x be the value of experience at any year. Then x+1 be the value of experience after 1 year.

Similarly, let y be the hourly pay rate for any random year. Then, Ynew = y + 1 be the hourly pay rate after 1 year.

Hence,

Ynew = 0.9(x+1) + 8.3

Increase in profit can be obtained by subtraction y from Ynew

Increase in profit = y - ynew = [0.9(x+1)+8.3] - 0.9x + 8.3

Increase in profit = 0.9 dollars per hour

(Can also be obtained by taking slope of given equation)

Part (b):

For zero years of Experience x = 0; equation (1) will become

y = 0.9(0) + 8.3

y = 8.3 dollars per hour

Part (c):

For seven years of Experience x = 7; equation (1) will become

y = 0.9(7) + 8.3

y = 14.6

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