Respuesta :
Answer:
Pump factor = Fp = 7.854 gal/cycle
Ev = 82.00 %
P_H = 183.29 hp
Explanation:
Given data:
Dimension of duplex pump
6.5 inch liner
2.5 inch rod
18 inch strokes
Pressure 3000 psig
Pit dimension
7 ft wide
20 ft long
Ls = 18 inch
Velocity = (18)/10
volumetric efficiency is given as E_v = (Actual flow rate)/(Theortical flow rate) * 100
we know that flow rate is given as = Area * velocity
Theoritical flow rate [tex]= \frac{\pi}{2}\times Ls(2d_l^2 - d_r^2)\times N[/tex]
[tex]Ev = \frac{7\times 12 \times 20\times 12\times 12 \times \frac{18}{10} inch^3/min}{\frac{\pi}{2} \times 18 (2\times 6.5^2 -2.5^2) \times 20}[/tex]
Ev = 82.00 %
Pump factor [tex]Fp = = \frac{\pi}{2}\times Ls(2d_l^2 - d_r^2)\times Ev[/tex]
[tex]Fp =\frac{\pi}{2} \times 18 (2\times 6.5^2 -2.5^2) \times 0.82[/tex]
Fp = 1814.22 in^3/cyl
Fp = 7.854 gal/cycle
Flow rate [tex]q = NFp = 20 \times 7.854 = 157.08 gal/min[/tex]
Power [tex]Ph = \frac{\DeltaP q}{1714} = \frac{3000 \times 157.08}{1714} = 274.93 hp[/tex]
