Answer:
The final pressure will be 6.99 N/m^ 2
Explanation:
Initial volume of tire = 2.00 L
Initial pressure of the tire = 7.00 × 10 5 N/m 2
Initial temperature of tire 31 °C
P1V1 = P2V2
7.00 × 10 5 N/m 2 × V1 = 101325×100 → V1 = 1.45×10^(-5) m^3 = 1.45×10^(-2) L
Therefore new pressure = initial pressure - (pressure of released gas filling the entire 2 L)
pressure of released gas filling the entire 2 L = 2 L/(7.00 × 10^5 N/m^ 2 × 1.45×10^(-5) m^3) = 1.197 ×10^(-4) N/m^2
New pressure = 7.00 × 10^5 N/m^2 - 1.197 ×10^(-4) N/m^2
= 6.99 N/m^ 2