Answer:
176.9N
Explanation:
The following data were given
wire length,L=37cm=0.37m
linear density=18g/m
tube length,=192cm=1.92m,
speed of sound,v=343m/s
Since it is an open-closed tube, the second harmonic frequency is expressed as
[tex]f_{3}=3(\frac{v}{4l} )\\f_{3}=3(\frac{343}{4*1.92})\\f_{3}=133.98Hz[/tex]
The relationship between the tension, linear density and second harmonic frequency is expressed as
[tex]f_{3}=\frac{1}{2l_{w}}\sqrt{\frac{T}{\alpha } } \\T=(f_{3}*2l_{w})^{2}\alpha \\T=(133.984*2*0.37)^{2}*18*10^{-3}\\T=176.9N[/tex]