Answer:
W= 2.08 x 10⁻¹⁷ J
Explanation:
Given that
Initial potential V₁ =185 V
Final potential V₂ = 55 V
We know that charge of the proton
q=1.6 x 10⁻¹⁹ C
Work done is given as
W= q ΔV
q=Charge
ΔV=Potential difference
W=Work done
Now by putting the values in the above equation then we get
W= 1.6 x 10⁻¹⁹ ( 185 - 55 ) J
W=208 x 10⁻¹⁹ J
W= 2.08 x 10⁻¹⁷ J
Therefore the work done will be 2.08 x 10⁻¹⁷ J.
