Respuesta :
Answer:
w_cycle = 13.68 KJ / cycle
Explanation:
Given:
- Steady power out-put W_out = 15.5 hp
- System executes 50 cycles/min
Find:
Determine the amount of work that is delivered during each cycle in kilo-joules
Solution:
- First we will convert the steady output into KW as follows:
W_out = 15.5 hp
The conversion factor is 1.36 KW per hp.
W_out = 15.5 [hp] * [KW] / 1.36 [hp]
W_out = 11.4 [KW] or [KJ/s]
- Given that there are 50 cycles in 60 sec. We will use direct proportionality to calculate the number of cycles per second:
50 cycles -----------> 60 s
x cycles -----------> 1 s
x = 50/60 = 0.8333 cycles /s
- Next we will compute the amount of work done per cycle:
w_cycle = W_out / x
w_cycle = 11.4 [KJ/s] * [s] / 0.8333 [cycles]
w_cycle = 13.68 KJ / cycle
The amount of work that is delivered during each cycle is 13.68 kilojoules per cycle.
What is thermodynamics?
It is a branch of science that deals with heat and work transfer.
A heat engine operating at a steady-state delivers a power output (W) of 15.5 hp.
The engine receives energy by heat transfer in the amount of Qh = 30.5 kJ during each cycle of operation from a high-temperature thermal reservoir at Th = 940 K.
The system is executing 50 cycles per minute.
W = 15.5 hp = 11.4 kJ/s
50 cycles in 60 seconds. Then in one second, the number of cycles will be
[tex]\rm Number \ of \ cycle = \dfrac{50}{60}\\\\Number \ of \ cycle = 0.833[/tex]
The work done per cycle will be
[tex]\rm W_c = \dfrac{W}{x}\\\\W_c = \dfrac{11.4}{0.8333}\\\\W_c = 13.68 \ \ kJ/cycle[/tex]
More about the thermodynamics link is given below.
https://brainly.com/question/7206767
