Answer:
Explanation:
charge q = 11 x 10⁻⁶ C
If the charge were inside the square , according to Gauss's law
electric flux through the walls of square wiil be
= q / ε
Now , the charge is lying just on one of the faces of the square,(10 cm above the center of a square of side length 20 cm) , only half the flux as mentioned above will pass through the square.
flux through the square
= 1/2 x (q / ε)
= 1/2 x (11 x 10⁻⁶ / 8.85 x 10⁻¹²)
= .6214 x 10⁶ weber.
