Answer:
[tex]a=-3449.67\frac{m}{s^2}[/tex]
Explanation:
The car is under an uniforly accelerated motion. So, we use the kinematic equations. We calculate the acceleration from the following equation:
[tex]v_f^2=v_0^2+2ax[/tex]
We convert the initial speed to [tex]\frac{m}{s}[/tex]
[tex]39\frac{km}{h}*\frac{1000m}{1km}*\frac{1h}{3600s}=10.83\frac{m}{s}[/tex]
The car stops, so its final speed is zero. Solving for a:
[tex]a=\frac{v_0^2}{2x}\\a=-\frac{(10.83\frac{m}{s})^2}{2(1.7*10^{-2}m)}\\a=-3449.67\frac{m}{s^2}[/tex]
