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A solution is prepared by mixing 50.0 mL of ethanol with 300.0 mL of water. What is the volume percent of ethanol in this solution? Assume volumes are additive.

Respuesta :

joseaaronlara

Answer:

The answer to your question is 14.3 %

Explanation:

Data

volume of ethanol = 50 ml

volume of water = 300 ml

volume percent = ?

Formula

Percent by volume = (volume of solute/volume of solution) x 100

Volume of solute = 50 ml

volume of solution = 300 + 50 = 350

Substitution

Percent by volume = (50/350) x 100

Simplification and result

Percent by volume = 14.3 %

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