Answer:
The answer to your question is 0.33 moles of H₃PO₄
Explanation:
Data
moles of Ca(OH)₂ = 0.050
moles of H₃PO₄ = ?
Process
1.- Write the balanced chemical equation
3Ca(OH)₂ + 2H₃PO₄ ⇒ Ca₃(PO₄)₂ + 6H₂O
Reactants Elements Products
3 Ca 3
12 H 12
14 O 14
2.- Calculate the moles of phosphoric acid
3 moles of calcium hydroxide --------------- 2 moles of phosphoric acid
0.5 moles of calcium hydroxide ----------- x
x = (0.5 x 2)/3
x = 0.33 moles
0.33 moles of H₃PO₄ need to be added to reach the equivalence point.
Given:
Moles of Ca(OH)₂ = 0.050
Moles of H₃PO₄ = ?
Balanced chemical equation:
3Ca(OH)₂ + 2H₃PO₄ ⇒ Ca₃(PO₄)₂ + 6H₂O
3 moles of calcium hydroxide gives 2 moles of phosphoric acid
0.5 moles of calcium hydroxide produces x moles of phosphoric acid
x = (0.5 * 2)/3
x = 0.33 moles
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