Respuesta :
Answer:
[tex] \bar X = \frac{\sum_{i=1}^n x_i}{n}[/tex]
Where n represent the sample size, on this case n =33. If we use this formula we got:
[tex] \bar X = 113.727[/tex]
And for this case we know that is the best estimator since is an unbiased estimator for the true population mean since we have this:
[tex] E(\bar X) = E(\frac{\sum_{i=1}^n x_i}{n})= \frac{1}{n} \sum_{i=1}^n E(X_i) = \frac{n\mu}{n} = \mu[/tex]
Step-by-step explanation:
For this case we have the following values given:
82, 96, 99, 102, 103, 103, 106, 107, 108, 108, 108, 108, 109, 110, 110, 111, 113, 113, 113, 113, 115, 115, 118, 118, 119, 121, 122, 122, 127, 132, 136, 140, 146
And we want to estimate the mean value of IQ for the conceptual population.
For this case we can use as estimator for the population mean the sample mean. We know that the sample mean is given by this formula:
[tex] \bar X = \frac{\sum_{i=1}^n x_i}{n}[/tex]
Where n represent the sample size, on this case n =33. If we use this formula we got:
[tex] \bar X = 113.727[/tex]
And for this case we know that is the best estimator since is an unbiased estimator for the true population mean since we have this:
[tex] E(\bar X) = E(\frac{\sum_{i=1}^n x_i}{n})= \frac{1}{n} \sum_{i=1}^n E(X_i) = \frac{n\mu}{n} = \mu[/tex]
Answer:
Step-by-step explanation:
well what i know is that the mean is by adding all numbers and then dividing it by the number of values that are in there
so....
82 + 96 + 99 + 102 + 103 + 103 +106 +107+108 +108+108+108,+ 109,+ 110,+ 110,+ 111,+ 113,+ 113,+ 113,+ 113,+ 115,+ 115, +118,+ 118,+ 119,+ 121,+ 122,+ 122, +127,+ 132,+ 136,+ 140,+ 146 = 3,753
3,753 divided by 33 = 113.72
if this was right but if it is pls mark brainlest pls
