Answer:
[tex]P_2=25.18\ lb/in^2[/tex]
Explanation:
Given that
P₁=27 lb/in² ,T₁=25⁰C=273+25 = 298 K
T₂=5⁰C = 273 + 5 = 278 K
Lets take final pressure = P₂
We know that if volume of the gas is constant then we can say that
[tex]\dfrac{P_2}{P_1}=\dfrac{T_2}{T_1}[/tex]
[tex]P_2=P_1\times \dfrac{T_2}{T_1}[/tex]
Now by putting the value in the above equation
[tex]P_2=27\times \dfrac{278}{298}\ lb/in^2[/tex]
[tex]P_2=25.18\ lb/in^2[/tex]
Therefore the new tire pressure will be
[tex]P_2=25.18\ lb/in^2[/tex]
