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An opera singer in a convertible sings a note at 600 Hz while cruising down the highway at 90km/hr. What is the frequency heard by a person standing beside the road in front of the car?

Respuesta :

Khoso123

Answer:

[tex]f=647.17Hz[/tex]

Explanation:

Given data

Frequency fs=600 Hz

Velocity Vs=90 km/hr =25 m/s

Speed of sound v=343 m/s

To find

Frequency f heard by a person standing beside the road in front of the car

Solution

From Doppler's effect we know that:

[tex]f=f_{s}(\frac{v+vL}{v+vs} )\\ as\\vL=0[/tex]

Here Vs is negative as the source is moving towards listener

[tex]f=fs(\frac{v+0}{v-vs} )\\f=(600Hz)(\frac{343m/s+0}{343m/s-25m/s} )\\f=647.17Hz[/tex]  

Cricetus

The frequency heard by person will be "647.17 Hz".

Given values:

  • Frequency, [tex]f_s = 600 \ Hz[/tex]
  • Velocity, [tex]V_s = 90 \ km/hr[/tex]

or,

                           [tex]= 25 \ m/s[/tex]

  • Speed of sound, [tex]v = 343 \ m/s[/tex]

By using the Doppler's effect, we get

→ [tex]f = f_s(\frac{v+vL}{v+v_s} )[/tex]

By substituting the values, we get

     [tex]= 600\times (\frac{343+0}{343-25} )[/tex]

     [tex]= 600\times \frac{343}{318}[/tex]

     [tex]= 647.17 \ Hz[/tex]

Thus the above frequency is right/

Learn more about frequency here:

https://brainly.com/question/14696233

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