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10 mol/s of ethylbenzene is compressed isentropically in a steady-flow process from 1 bar and 200°C to 14 bar. Assuming an ideal gas at all times, find the final temperature. (An ideal gas at 14 bar?

Respuesta :

Answer:

Explanation:

Given ;

  • n = 10mols, P1 = 1 bar, P2 = 14 bar, T1 = 200degree Celsius = 473K
  • for reversible adiabatic Q = 0
  • W = γ/γ - 1 x P1V1 [ 1 - (P2/P1)^γ-1/γ]
  • Heat capacity ratio of ethyl benzene = γ = 1.05332
  • molar mass of ethyl benzene = 106g/mol
  • plugging the values in the above equation, W = -110988.12WATT

From first law ; Q - W = MCp dT

  • Cp = 1.55J/gk = heat capacity of ethyl benzene
  • M = number of moles X molar mass
  • = 10mol/s X 106g/mol = 1060gs

plugging the values in the new equation ;

  • Q - W = nCp(T2 - T1)
  • T2 = 540.5K = final temperature

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