Answer: 0.129J(gioc)
Explanation:
The basic formula for specific heat is Q=MC∆t, where m is the mass, C is the specific heat, and ∆t is the change in temperature.
The parameters given are Q= 3000j = 3kj, mass is 0.465 and ∆t is (100-50)= T2-T1
By imputing them we have;
Q=MC∆T
30= 0.465xCx(100-50)
3=23.25C
C= 3/23.25
=0.129J(gioC
Using the formula of specific heat, the specific heat of the substance described is 0.129J(gi°c) (Option C)
Specific Heat is described in chemistry as the amount of heat necessary to raise the temperature of a given substance's unit mass by a particular amount (usually one degree).
We arrive at the solution by using the basic formula for specific heat ⇒ Q = MC∆t,.
It is to be noted that:
m = mass,
C = specific heat, and
∆t = change in temperature.
The parameters given are Q= 3000j = 3kj, mass is 0.465 and ∆t is (100-50)= T2-T1
Inserting the values for the factors above, we have:
30= 0.465 x C x (100-50)
Divide both sides by 10 we have
3 = 23.25C
Make "C" the subject of the formula and we have
C = 3/23.25
Hence,
=0.129J (gi°C)
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