Answer:
2/3
Explanation:
When two heterozygous plants (let's suppose Tt and Tt) are crossed, the progeny exhibits dominant and recessive phenotype in a 3 : 1 ratio respectively. This occurs since T and t alleles present together in the heterozygous parent plant segregate from each other and are distributed to the different gametes.
Cross Tt x Tt= 1/4 TT: 1/2 Tt: 1/4 tt
Considering the genotype of the F2 progeny, there is 2/3 heterozygous dominant progeny (Tt) out of a total of 3/4 dominant progeny. This heterozygous dominant progeny would give a 3:1 ratio of dominant and recessive progeny upon self-fertilization.