Answer:
T'=46.6 K
Explanation:
Let T be the temperature of a hot reservoir, T' be the temperature of cold reservoir.
For a Carnot's engine, efficiency can be calculated as follows:
[tex]\eta=\frac{W}{Q}=1-\frac{T'}{T}[/tex]
Where, W is the amount of work done, Q is the amount of heat extracted from the hot reservoir.
Substitute the values: W= 8.0 J
Q = 10.0 J
T = 233 K
[tex]\frac{8}{10}=1-\frac{T'}{233K}\\\Rightarrow 0.8 = 1-\frac{T'}{233K}\\\\\Rightarrow T' = 0.2 \times 233 K\\\Rightarrow T'=46.6 K[/tex]
Thus, the temperature of the cold reservoir is 46.6 K.
