Respuesta :
Answer: The period doubles.
Explanation: this is a question on the relationship between the period (T) of a loaded spring and it mass (m), the formulae relating both quantities is given below.
T =2π * √m/k
Where T= period, m= mass and k = spring constant.
By squaring both sides, we have
T² = 4π² * m/k
T² = (4π²/k) * m
The expression (4π²/k) is a constant, hence
T² = K *m... This implies that square of period is proportional to mass.
Hence
(T1)²/m1 = (T2)²/m2
From the question, m2 =4m1 and we are to find T2.
(T1)²/m1 = (T2)²/4m1
(T1)² = (T2)²/4
4(T1)² = (T2)²
T2 =√4(T1)²
T2 = 2T1
this implies that T2 is twice or double T1
If the mass of the attached body is increased by a factor of four. What is true about the period is that the period will remain unchanged. The correct answer is option A
The Physics explanation behind the relationship between the mass and the period is that period T does not not depends on the mass of an object but depends on the length of the rope or the string in which the mass of the body is attached.
If the mass of the attached body is increased by a factor of four. What is true about the period is that the period will remain unchanged.
That is, if we have four different pendula of the same length but of different masses attached to the different string, the pendula will produce the same period.
From simple pendulum formula
Period T = 2π[tex]\sqrt{\frac{L}{g} }[/tex]
From the above formula, we can therefore conclude that period T does not depend on mass but length of the string. So, If the mass of the attached body is increased by a factor of four. What is true about the period is that the period will remain unchanged.
Answer is option A
Learn more here: https://brainly.com/question/14932567
