Answer:
The probability that a randomly selected family owns a dog, given that it doesn't own a cat, is approximately 21.12%.
Step-by-step explanation:
Let P(D) be the event that a randomly selected family owns a dog.
Let P(C) be the event that a randomly selected family owns a cat.
Then: probability is
P (D) = 0.20
P(C) = 0.29
P(C|D) = 0.25
So, as we know
P(D|¬ C) = P ( D ∩ ¬ C )/ P ( ¬ C )
then,
P(D|¬ C) [tex]=\frac{P(D)*(1-P(C|D))}{1-P(C)}[/tex]
[tex]=\frac{(0.20)*(1-(0.25))}{1-0.29}[/tex]
[tex]=0.2112\\[/tex]
Then, the probability that a random selected family owns a dog is 0.2112
[tex]=21.12\%[/tex]