The functions f(x) = -2x + 2 and g(x) = (1/3)^x are shown in the graph.

What are the solutions to -2x + 2 = (1/3)^x + 1?
(Multiple choice)

A. -1
B. 0
C. 2
D. 3
E. 4

The functions fx 2x 2 and gx 13x are shown in the graph What are the solutions to 2x 2 13x 1 Multiple choice A 1 B 0 C 2 D 3 E 4 class=

Respuesta :

Option a: -1

Option b: 0

Explanation:

The function [tex]f(x)=-2 x+2[/tex] and [tex]g(x)=\left(\frac{1}{3}\right)^{x}+1[/tex]

To determine the solution of [tex]-2 x+2=\left(\frac{1}{3}\right)^{x}+1[/tex] and solving the expression using lambert's form, we get the solution [tex]x=-1, x=0[/tex]

Hence, the solution to the functions [tex]f(x)=-2 x+2[/tex] and [tex]g(x)=\left(\frac{1}{3}\right)^{x}+1[/tex] are -1 and 0.

Also, by looking at the graph, we can see that, the graphs f(x) and g(x) intersect at the points [tex](-1,4)[/tex] and [tex](0,2)[/tex].

Hence, the solution to [tex]-2 x+2=\left(\frac{1}{3}\right)^{x}+1[/tex] is -1 and0.

Thus, Option a and Option b are the correct answers.