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You rub two 2.0-g balloons with a wool sweater. The balloons hang from 0.50-m-long very light strings. When you attach the strings together at the top, the balloons hang away from each other each string making an angle of 37∘ with the vertical.
Determine the magnitude of the electric force between the two charges?

Respuesta :

Answer:

[tex]F_e = 0.0147\ N[/tex]

Explanation:

given,

mass of balloons, m = 2 g

Length of the string, L = 0.5 m

angle made with vertical,θ = 37°

Magnitude of electric force, F = ?

Let F_e be the magnitude of the electric force between the balloons.

 T cos 37° = mg----------(1)

 T sin 37° = Fe------------(2)

dividing equation (2) by (1)

[tex]\dfrac{sin 37^0}{cos 37^0}=\dfrac{F_e}{m g}[/tex]

[tex]F_e =m g tan 37^0[/tex]

[tex]F_e = 0.002\times 9.8\times tan 37^0[/tex]

[tex]F_e = 0.0147\ N[/tex]

Magnitude of force between the two electric force is equal to [tex]F_e = 0.0147\ N[/tex]

Ver imagen wagonbelleville