Answer:
153.3 g
Explanation:
Density = 1.01 g/mL
Volume - 4.6 L
1 L = 1000 mL
Volume in mL = 4.6 × 1000 = 4600 mL
Mass = density × volume
= 1.01 g/mL × 4600 mL
= 4,646 g
[tex]AgNO_3[/tex] contains 3.3% Ag
Mass of Ag in [tex]AgNO_3[/tex] = 4,646 g × 0.033
= 153.318 g
= 153.3 g
Maximum amount of silver (in grams) that can be plated out is 153.3 g