Answer:
[tex]SQ\not=2OM\\\\Sam\ is\ not\ Correct.[/tex]
Step-by-step explanation:
Pythagorean Theorem: In a right triangle the square of longest side(hypotenuse) is equal to the sum of the squares of the other sides.
[tex]In\ \triangle SQR\\\\Hypotenuse=SQ\\\\SQ^2=QR^2+RS^2\\\\SQ^2=6^2+12^2\\\\SQ^2=180\\\\SQ^2=36\times 5\\\\SQ^2=6^2\times 5\\\\SQ=6\sqrt{5}\approx 13.42[/tex]
[tex]In\ \triangle OLM\\\\Hypotenuse=OM\\\\OL=LM=6\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ Sides\ of\ a\ square\\\\OM^2=OL^2+LM^2\\\\OM^2=6^2+6^2\\\\OM^2=72\\\\OM=6\sqrt{2}\approx 8.49[/tex]
[tex]2\times OM=16.97>SQ\\\\\Rightarrow SQ\not=2OM\\\\Sam\ is\ not\ Correct[/tex]
