Given that AC=30, AB=5x-21, BC=3y+4, CD=2x-3, and DA=4x+1, find the indicated variables for each question. find Values X, Y and Z
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Answer:3x + 4 = x+ 8 > 3x - x = 2x > 2x + 4 = 8 > 8 - 4 = 4 > 2x / 2 crosses out > 4 / 2 = 2 > x=2
2y + 5 = y + 7 > 2y - y = y > y+ 5 = 7 > 7-5= 2 > y=2
the perimeter of the kite is 4
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If AC = 30, AB = 5x-21, BC = 3y+4, CD = 2x-3, and DA = 4x+1 then the values of x = 6, y = 7, z = 23.
Let, AC = 30, AB = 5x-21, BC = 3y+4, CD = 2x-3, and DA = 4x+1
If ÀC = z + 7
the substitute the value of AC = 30
30 = z + 7
30 - 7 = z
The value of z = 23.
If CD = 2x - 3
then, AB = CD
the substitute the value of AB = 5x-21
2x - 3 = 5x - 21
21 - 3 = 5x -2x
18 = 3x
x = 18÷3
The value of x = 6
If DA = 4x+1 and BC = 3y+4
4x + 1 = 3y + 4
By substituting the value of x, we get
4(6) + 1 = 3y + 4
25 = 3y + 4
3y = 25 - 4
y = 21 ÷ 3
The value of y = 7.
Therefore, the value of x = 6, y = 7, z = 23.
To learn more about the variables and functions
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