Answer:
8.36 m/sec
Explanation:
Since muzzel velocity is required to be determined i-e velocity with which bullet leaves the gun. So we have to suppose that bullet has no acceleration and moves with constant velocity.
a=0 m/sec2
Vi=0 (initially the bullet is at rest)
S= 3.27 m
using m/s
S= Vit+1/2at2
==> 3.27 = 0+0.5×[tex]t^{2}[/tex]
==> [tex]t^{2}[/tex] = 6.54
==> t=2.56 sec
Now using S= V×t
==> V = S/t
==> V= 3.27 × 2.56 = 8.36 m/sec
