What is the height of the trapezoid if the area was 26 units
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Answer:
h = 4
Step-by-step explanation:
The area (A) of a trapezoid is calculated as
A = [tex]\frac{1}{2}[/tex] h( a + b) ← a and b are the parallel bases
here a = 5, b = 8 and A = 26, thus
[tex]\frac{1}{2}[/tex] h(5 + 8) = 26, that is
[tex]\frac{1}{2}[/tex] h × 13 = 26 ( divide both sides by 13 )
[tex]\frac{1}{2}[/tex] h = 2 ( multiply both sides by 2 to clear the fraction )
h = 4