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A household refrigerator with a coefficient of performance of 2.4 removes energy from the refrigerated space at a rate of 600 Btu/h. Evaluating electricity at $0.08 per determine the cost of electricity in a month when the refrigerator operates for 360 hours

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adetoseen

Answer:

$720

Step-by-step explanation:

Coefficient of performance of a refrigerator (COP) =[tex]\frac{desired ouput}{Required inpu}[/tex]

desired out i.e energy removed = 600Bth/hr

Required input=?

2.4=[tex]\frac{600}{required inpu}[/tex]

required input=[tex]\frac{600}{24}[/tex]=25Btu/hr

cost of electricity per hour = $0.08

cost of electricity for 360 hours =$0.08×360=$28.8

for an input of 25Btu/hr and 360 hours

∴cost of electricity in month =$28.8×25=$720

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