Imagine a kid sitting in a soap box. The moment it tosses a stone away to the left, the soap box, along with the kid, moves to the right. If the kid pushes against the stone with a force of 20 N in the moment of the toss, what will be the acceleration of the system kid+soap box? The kid's mass is 50 kg and the soap box's 10 kg.

Respuesta :

The acceleration of the system is [tex]0.33 m/s^2[/tex]

Explanation:

In this problem, the kid sitting in the  soap box pushes against the stone with a force of 20 N.

According to Newton's third law of motion, when a force is applied on object, the object pushes back with an equal and opposite force: therefore in this case, the kid (and the soap box) also experience a force of 20 N forward.

Then, we can use Newton's second law of motion to find the acceleration of the kid+soap box system:

[tex]F=ma[/tex]

where:

F = 20 N is the net force on the system

m = 50 + 10 = 60 kg is the total mass of the system

a is the acceleration of the system

And solving for a, we find:

[tex]a=\frac{F}{m}=\frac{20}{60}=0.33 m/s^2[/tex]

Learn more about force and acceleration:

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