n / 10 +7 =10. plz answer this I need help

What I am looking for in this problem is the easiest way to isolate [tex]n[/tex] on one side of this equation. For me, the way to solve problems like this one came with experience, so often I automatically have a system that I follow for solving equations like this one without trouble. What I'm saying is that as long as you understand the rules of different operations like multiplication, addition, subtraction, etc, you have several ways to solve for
Anyways, let's start by moving our integers not being multiplied or divided to one side, and anything being multiplied or divided to the other. In this case, that is canceling out our [tex]7[/tex] on the left side of the problem by subtracting on both sides, like so.

[tex]\frac{n}{10}+7=10\\\frac{n}{10}+7-(7)=10-(7)[/tex]

[tex]\frac{n}{10}=3[/tex]

Now, things are more straightforward. All I need to do is get rid of the denominator below [tex]n[/tex]. This is very simple, I just need to multiply what's on the denominator onto both sides. I'll show how the math works, but if this confuses you, just know that doing this will cancel out the denominator.

[tex]\frac{n}{10}=3\\\frac{n}{10}(10)=3(10)\\\frac{n}{10}(\frac{10}{1})=30\\\frac{10n}{10}=30\\[/tex]

Because [tex]n[/tex] is both being multiplied and divided by the same number, these two operations cancel out, leaving us with just

[tex]n=30[/tex]

Double Checking Your Work:

If we assume that both [tex]\frac{n}{10}+7=10[/tex] and [tex]n=30[/tex] are true, then we can try substituting [tex]30[/tex] into our equation and seeing if it is equal.

[tex]\frac{n}{10}+7=10\\n=30[/tex]

[tex]\frac{(30)}{10}+7=10[/tex]

[tex]10[/tex] goes into [tex]30[/tex] three times, so [tex]\frac{30}{10}=3[/tex].

[tex]3+7=10\\10=10[/tex]

n / 10 +7 =10. plz answer this I need help​