Answer:
Less than 8% of test takers will take longer than 150 minutes to finish the test.
Step-by-step explanation:
We are given the following information in the question:
Mean, μ = 125 minutes
Standard Deviation, σ = 18 minutes
We are given that the distribution of length of time is a bell shaped distribution that is a normal distribution.
Formula:
[tex]z_{score} = \displaystyle\frac{x-\mu}{\sigma}[/tex]
We have to find the value of x such that the probability is 0.92
[tex]P( X < x) = P( z < \displaystyle\frac{x - 125}{18})=0.92[/tex]
Calculation the value from standard normal z table, we have,
[tex]P(z < 1.405) = 0.92[/tex]
[tex]\displaystyle\dfrac{x - 125}{18} = 1.405\\\\x = 150.29 \approx 150[/tex]
Thus, less than 8% of test takers will take longer than 150 minutes to finish the test.