6. Two double-stranded fragments of DNA are exactly the same length. At 89°C, fragment A has completely denatured, which means that the two strands have separated. At that temperature, fragment B is still double-stranded A. How might these fragments differ, to result in different denaturation temperatures? (2 points) B. Determine the nucleotide composition of fragment A. (4 points)

Question

14-02-2020
Biology

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6. Two double-stranded fragments of DNA are exactly the same length. At 89°C, fragment A has completely denatured, which means that the two strands have separated. At that temperature, fragment B is still double-stranded A. How might these fragments differ, to result in different denaturation temperatures? (2 points) B. Determine the nucleotide composition of fragment A. (4 points)

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Answer:

A. fragment A has lower proportion of G-C which has 3-Hydrogen bonding,(high energy bonding) but more of A-T bonding of 2-Hydrogen bindings(low energy bonding). Therefore denatures at 89 degree,Lower bonding energy allow denaturation at low temperature .

B. There is likelihood of fragment A having high proportion of A-T, but lower proportion of fragment G-C,

Structurally the G-C hydrogen bonds is three in number, while 2 hydrogen bonds joined n A-T bases. This variation in number of hydrogen bonding ensures stability of Guanine-Cytosine bonds and therefore high resistance to heat compare to Adenine-Cytosine bonds.

Consequently, fragments A must contain higher proportion of lower hydrogen number A-T complementary bases, compare to higher number of H-bonding Guanine-Cytosine Base complementary.thus low energy, with low resistance to heat, and therefore unwinding of its double helix.

However, the higher proportion of G-C compare to A-T in fragment B , aids its high resistance to heat, high temperature to overcome the high bonding energy and therefore its stability to heat, and failure to unwind at the same temperature,

Explanation: