Note: The missing diagram is attached below for a reference.
Answer:
- Δ [tex]TUW[/tex] ≅ Δ[tex]VWU[/tex] by [tex]AAS[/tex] case.
Step-by-step explanation:
Given:
- ∠T and ∠V are right angles.
- [tex]TW[/tex]║ [tex]VU[/tex]
To Prove:
- Δ [tex]TUW[/tex] ≅ Δ[tex]VWU[/tex]
As
∠ [tex]T[/tex] ≅ ∠ [tex]V[/tex] ≅ [tex]90^{0}[/tex] (Given)
Side [tex]UW[/tex] ≅
[tex]TW[/tex]║ [tex]UV[/tex]
and [tex]UW[/tex] is a transverse
So,
∠ [tex]TWU[/tex] ≅ ∠ [tex]WUV[/tex] [tex]\left[alternate\:\:interior\:\:angles\right][/tex]
[tex]As\:Angle\:=\:Angle\:=\:side\:are\:equal[/tex]
Thus,
- Δ [tex]TUW[/tex] ≅ Δ[tex]VWU[/tex]
Keywords: proof, paragraph, logic, reason
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