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Two identical point charges are fixed to diagonally opposite corners of a square that is 0.510 m on a side. Each charge is 3.03 10-6 C. How much work is done by the electric force as one of the charges moves to an empty corner?

Respuesta :

Answer:

Workdone = 0.05Joules

Explanation:

The side of a square =a= 0.510m

q1=q2=3.03×10^-6C

W=UF-Ui

W= kq1q2/a - kq1q2/r

But r= sqrt(a^2+a^2)=sqrt2a

W=kq1q2/a - kq1q1/sqrt2a

W= kq1q2/a (1 -1/sqrt2)

W= (9×10^9)(3.03×10^-6)(3.03×10^-6)(1-1/sqrt2)

W= 0.05Joules

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