Respuesta :
Answer:
0.0838 (8.62%)
Step-by-step explanation:
defining the event G= an out-of-state transaction took place in a gasoline station , then the probability is
P(G) = probability that the transaction is fraudulent * probability that took place in a gasoline station given that is fraudulent + probability that the transaction is not fraudulent * probability that took place in a gasoline station given that is not fraudulent = 0.033 * 0.092 + 0.977 * 0.034 = 0.0362
then we use the theorem of Bayes for conditional probability. Defining also the event F= the transaction is fraudulent , then
P(F/G)=P(F∩G)/P(G) = 0.033 * 0.092 /0.0362 = 0.0838 (8.62%)
where
P(F∩G)= probability that the transaction is fraudulent and took place in a gasoline station
P(F/G)= probability that the transaction is fraudulent given that it took place in a gasoline station
Answer:
Step-by-step explanation:
- let F = fraud credit card transaction and G = legit credit card transaction
- C =credit card transaction at gasoline station
- P(G) = 0.977
- P(F) = 1 - P(G) = 0.023
- P(C|G) = 0.034
- P(C|F) = 0.092
To find what is the probability the transaction is fraudulent = P(F|C)
From application of baye's rule ;
P(F|C) = P(F) P(C|F) / P(F) P(C|F) + P(G) P(C|G)
= 0.092 X 0.023 / 0.023 X 0.092 + 0.097 X 0.034
= 0.0599 is the probability the transaction is fraudulent