Answer:
The speed is equals to 22.49 m/s
Explanation:
Given Data:
[tex]Area = A=2.54*10^-^3m^2\\Force = F = 1.01*10^4N\\density = p = 7860 kg/m^3[/tex]
Required:
Speed of Traverse wave = c =?
Solution:
As we know that
[tex]p=m/V\\\\ p=m/(L*A)\\p*A=m/L[/tex]
Now the equation for speed of traverse wave is calculated through:
[tex]\sqrt \frac{F*L}{m}\\[/tex]
=[tex]\sqrt\frac{F}{m/L} \\\sqrt{} \frac{F}{p*A}[/tex]
Substituting the values
[tex]\sqrt\frac{1.01*10^4}{7860*2.54*10^-^3} \\[/tex]
=22.49 m/s
