contestada

Find the ratio of speeds of an electron and a negative hydrogen ion (one having an extra electron) accelerated through the same voltage, assuming non-relativistic final speeds. Take the mass of the hydrogen ion to be 1.67×10^{-27} kg.

Respuesta :

Answer:

42.8

Explanation:

A particle travelling through potential difference V has energy E =qV = 1/2mv²

v = √(2qV / m)

ve = √(2qV / me)

vh = √(2qV / mh)

ve / vh = √( (2qV / me) ÷(2qV / mh) = √ ( mh / me ) where mh = mass of hydrogen ion and me is mass of electron, V voltage is the same, ve is speed of electron and vh is the speed of hydrogen ion

ve / vh  = √ ( mh / me )  = √ ( 1.67 × 10⁻²⁷ kg) / ( 9.11 × 10 ⁻³¹ kg) = 42.8

Otras preguntas