A sea lab is 5 meters high and is designed to withstand submersion to 150 meters, measured from sea lavel to top of the sea lab. Calculate the pressure on top of the sea lab and the pressure variation on the side of the container measured as the dista

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Answer

given,

Height of the lab, h = 5 m

Depth up to which it can withstand Pressure,D = 150 m

Pressure on the top of lab when it is placed at 150 m depth

[tex]P = P_a + \rho g D[/tex]

P_a is atmospheric pressure, 1.01 x 10⁵ Pa

density of the sea water = 1020 Kg/m³

[tex]P = 1.01\times 10^5+1020\times 9.8\times 150[/tex]

    P = 1600 kPa

now, Pressure variance on the side of the contained at distance 'x'

  [tex]Pressure\ variance = \rho_{sea}g(D +x)[/tex]

                                          =[tex]1020\times 9.81\times (150+x)[/tex]

                                          =[tex]10006.2 (150+x)\ N/m^2[/tex]

  [tex]Pressure\ variance = 10(150 +x)\ kN/m^2[/tex]