Respuesta :
Explanation:
(a) It is known that formula for electric dipole moment is as follows.
p = qd
= [tex]1.50 \times 10^{-9} \times 6.2 \times 10^{-6}[/tex]
= [tex]9.30 \times 10^{-15} Cm[/tex]
Hence, magnitude of the electric dipole moment is [tex]9.30 \times 10^{-15} Cm[/tex].
(b) Now, formula to calculate the difference in potential energy is as follows.
[tex]\Delta U = U_{F} - U_{I}[/tex]
= -pE Cos 180 + pE Cos 0
= 2pE
= [tex]2 \times 9.30 \times 10^{-15} Cm \times 1100 N/C[/tex]
= [tex]2.05 \times 10^{-11} J[/tex]
Thus, we can conclude that difference between the potential energies for dipole orientations parallel and antiparallel to E is [tex]2.05 \times 10^{-11} J[/tex].
a. The magnitude of the electric dipole moment is [tex]9.3*10^{-12}[/tex] C-m
b. The difference between the potential energies for dipole orientations parallel and antiparallel to E is [tex]18.6*10^{-12}[/tex] C-m
a. The electric dipole is calculated as,
[tex]P=q*d[/tex]
Where q is charge and d is distance between charges.
Given that, [tex]q=1.5nC=1.5*10^{-9}C,d=6.2mm=6.2*10^{-3}m[/tex]
Substitute values in formula,
[tex]P=1.5*10^{-9}*6.2*10^{-3}=9.3*10^{-12} C-m[/tex]
b. The difference between the potential energies for dipole orientations parallel and antiparallel to E is,
[tex]V=qd*cos(0)-qd*cos(180)\\\\V=qd+qd=2qd=2P[/tex]
[tex]V=2P=2*9.3*10^{-12} =18.6*10^{-12}[/tex]
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