contestada

The amusement park ride shown above takes riders straight up a tall tower and then releases an apparatus holding seats. This apparatus free-falls back to Earth and is stopped safely right above the ground. Which of the following indicates the magnitude of the gravitational force exerted on a rider of mass m on the way up and on the way down?

Respuesta :

skyluke89

The gravitational force on the rider is:

- Way up: equal to mg

- Way down: equal to mg

Explanation:

The choices are missing: find them in the attached figure.

The force of gravity acting on a body is a force directed downward (towards the Earth's centre) and whose magnitude is

[tex]F=mg[/tex]

where

m is the mass of the body

g is the acceleration due to gravity

The value of g is approximately constant near the Earth's surface and it is

[tex]g=9.8 m/s^2[/tex]

During the ride, the mass of the rider, m, remains constant. This means that the magnitude of the gravitational force, mg, exerted on the rider remains constant during the rider.

Therefore, the correct answer is

- Way up: equal to mg

- Way down: equal to mg

Learn more about force of gravity:

brainly.com/question/1724648

brainly.com/question/12785992

#LearnwithBrainly

Ver imagen skyluke89

In both way up and way down the magnitude is equal to mg.

  • Way up  and Way down is equal to mg both indicate the magnitude of the gravitational force exerted on a rider of mass m on the way up and on the way down.
  • On both way up and way down the magnitude of the gravitational force are the same because mass of the body does not change with height.
  • So in both cases the magnitude of the gravitational force is F= mg so we can conclude that both way up and way down the magnitude is equal to each other.

Learn more: https://brainly.com/question/14775238

Otras preguntas