Answer:
2.[tex]d'=\frac{d}{\sqrt2}[/tex]
Explanation:
The electric force between two point charges is given by Coulomb's law:
[tex]F=\frac{kq_1q_2}{d^2}[/tex]
Here k is the Coulomb constant, [tex]q_1[/tex] and [tex]q_2[/tex] are the signed magnitudes of the charges and d the distance of separation between them. We need [tex]F'=2F[/tex]. So:
[tex]F'=\frac{kq_1q_2}{d'^2}\\2F=\frac{kq_1q_2}{d'^2}\\2\frac{kq_1q_2}{d^2}=\frac{kq_1q_2}{d'^2}\\2d'^2=d^2\\d'=\frac{d}{\sqrt2}[/tex]
