Respuesta :
Answer:
c. execution falls through the next branch until a break statement is reached
Explanation:
In a switch statement, if break is missing, then program continues to the next cases until it finds a break statement.
Consider the following example!
Example:
#include <iostream>
using namespace std;
int main()
{
int choice = 1;
switch (choice)
{
case 1:
printf("This is case 1, No break\n");
case 2:
printf("This is case 2, No break\n");
case 3:
printf("This is case 3, with break\n");
break;
default: printf("Error! wrong choice\n");
}
return 0;
}
Output:
This is case 1, No break
This is case 2, No break
This is case 3, with break
We have 3 cases here and case 1 and 2 don't have break statements, only case 3 has a break statement.
We called the case 1, then program continued to case 2, and finally to case 3 where it finds the break statement and terminates.
Therefore, we conclude that in a switch statement, if a break statement is missing, then execution falls through the next branch until a break statement is found.
