When a constant force acts upon an object, the acceleration of the object varies inversely with its mass. When a certain constant force acts upon an object with mass 4 kg, the acceleration of the object is 5 /ms2. If the same force acts upon another object whose mass is 10 kg, what is this object's acceleration?

Respuesta :

Answer:

[tex]a = 2 \frac{m}{s^2}[/tex]

Step-by-step explanation:

Knowing that [tex]F = ma[/tex] being [tex]m[/tex] the mass and [tex]a[/tex] the acceleration we have:

"When a certain constant force acts upon an object with mass 4kg the acceleration of the object is [tex]5 \frac{m}{s^2}[/tex]"

We can calculate that force as: [tex]F = ma = (4Kg) (5\frac{m}{s^2}) = 20 Kg\frac{m}{s^2} = 20 N[/tex]

Now, that force is being aplied to another objet whose mass is 10 Kg and we want to know its acceleration.

Clearing [tex]a[/tex] from the force equation we have:

[tex]a = \frac{F}{m}[/tex]  ("The acceleration of the object varies inversely with its mass")

Then,

[tex]a = \frac{F}{m} = \frac{20N}{10Kg} =2 \frac{m}{s^2}[/tex]